Algebra Essay Example | Topics and Well Written Essays - 1000 words - 1

Algebra - Essay Example After doing the calculations (shown above), the answers to the first two expressions turned out to be identical. This is because both the expressions are identities as shown below: The third expression consisted of a fraction, and both were solved simultaneously. After all the values were plugged in the fraction and the final fraction was obtained, it was reduced to its lowest terms by dividing the numerator and the denominator by a common divisor which in this case was 3. Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing your math work.): The formula to calculate dose for a child is where D is the adult dosage and a is the child’s age. In order to solve the equation, the given values should be substituted in place of the variables. For part a, D = 75 and a = 5. Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing your math work.): To specify the equation of a line, gradient and the y-intercept is required. A parallel line has the same slope as the original line but do not pass through any point of the original line. In the case of y = x + 4, the slope is 1, therefore a parallel line would also have the same slope. The y-intercept is found by plugging the values in the ordered pair. The equation of the parallel line is y = x+8. On the other hand, a perpendicular line cuts the line in such a way that a right angle is formed at the point of intersection. The product of the gradients of the perpendicular lines is equal to -1, which means that the gradient of the perpendicular line is negative reciprocal of the gradient of the original line. In the case of the given equation, the perpendicular line